賦值錯誤c語言,c語言賦值失敗

本文目錄一覽：

• 1、c語言編程 賦值錯誤
• 2、C語言 關於賦值錯誤的問題
• 3、C語言結構賦值報錯。
• 4、C語言 數組指針賦值出錯

c語言編程 賦值錯誤

scanf函數要求輸入時與雙引號內的格式完全一致，例如你寫的

scanf(“%d,%d,%d,%d”,a,b,c,d);

輸入時就應該寫

1,2,3,4

這樣的（注意逗號要用英文的逗號）

C語言 關於賦值錯誤的問題

if((a=b)((b-a+1)=N)(((a+b)*(b-a+1))/2=M))

這句語句錯了，我不知道你是不是想寫成(((a+b)*(b-a+1))/2==M)（=變成==）

這個的錯誤是，等號前面是表達式，表達式的結果是一個臨時變數，你把M賦值給一個臨時變數，肯定錯了。臨時變數不能做左值

要不改成==，表示相等，如果就是賦值，把M寫前面就可以了，把運算的值賦給M

C語言結構賦值報錯。

您好哦，這樣的：

main(void)

{

struct convert

{

double C[3][3];

};

struct convert con[24]=

{

{1,0.0,0.0,0.0,1.0,0.0,0.0,0.0,1.0},

{0.0,0.0,-1.0,0.0,-1.0,0.0,-1.0,0.0,0.0},

{0.0,0.0,-1.0,0.0,1.0,0.0,1.0,0.0,0.0},

{-1.0,0.0,0.0,0.0,1.0,0.0,0.0,0.0,-1.0},

{0.0,0.0,1.0,0.0,1.0,0.0,-1.0,0.0,0.0},

{1.0,0.0,0.0,0.0,0.0,-1.0,0.0,1.0,0.0},

{1.0,0.0,0.0,0.0,-1.0,0.0,0.0,0.0,-1.0},

{1.0,0.0,0.0,0.0,0.0,1.0,0.0,-1.0,0.0},

{0.0,-1.0,0.0,1.0,0.0,0.0,0.0,0.0,1.0},

{-1.0,0.0,0.0,0.0,-1.0,0.0,0.0,0.0,1.0},

{0.0,1.0,0.0,-1.0,0.0,0.0,0.0,0.0,1.0},

{0.0,0.0,1.0,1.0,0.0,0.0,0.0,1.0,0.0},

{0.0,1.0,0.0,0.0,0.0,1.0,1.0,0.0,0.0},

{0.0,0.0,-1.0,-1.0,0.0,0.0,0.0,1.0,0.0},

{0.0,-1.0,0.0,0.0,0.0,1.0,-1.0,0.0,0.0},

{0.0,1.0,0.0,0.0,0.0,-1.0,-1.0,0.0,0.0},

{0.0,0.0,-1.0,1.0,0.0,0.0,0.0,-1.0,0.0},

{0.0,0.0,1.0,-1.0,0.0,0.0,0.0,-1.0,0.0},

{0.0,-1.0,0.0,0.0,0.0,-1.0,1.0,0.0,0.0},

{0.0,1.0,0.0,1.0,0.0,0.0,0.0,0.0,-1.0},

{-1.0,0.0,0.0,0.0,0.0,1.0,0.0,1.0,0.0},

{0.0,0.0,1.0,0.0,-1.0,0.0,1.0,0.0,0.0},

{0.0,-1.0,0.0,-1.0,0.0,0.0,0.0,0.0,-1.0},

{-1.0,0.0,0.0,0.0,0.0,-1.0,0.0,-1.0,0.0},

};

return 0;

}

C語言 數組指針賦值出錯

char *string[20];這樣聲明的是一個名為string的數組，這個數組有20個元素，每一個元素都是一個char *型指針。所以數組裡存放的是「指針」，只是個4位元組變數，它還沒有指向，就不能用string[i][j]=’\0′;這種辦法給它的指向目標賦值。要麼直接把char *string[20];改成char string[20][100];(可以存放20個長99的字元串)，要麼在char *string[20];後用malloc等函數分別為20個指針分配空間。