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用Java設計一個小學算術運算測試軟體
你的想法是好的，但是我仔細構思了一遍，太難了。
首先難點就是怎麼生成題目。也是最難得，因為有太多不確定，弄不好就會出現負數結果的題目。
然後是題目的解答，這個難點就不說了，這個我在幾年前就寫好了。一直沒用上，現在卻用上了。
還有，你要窗體，可是我不會用swing
還有你要的四則混合運算是多長的，我總不能寫一個有1000多個數字寫成的式子吧。
題目中是否涉及到小數
下面是我的計算代碼：
package compute;
public class CaculateString {
private String str, s;
private int p1, p2;
public CaculateString(String str) {
this.str = str;
this.clear();
this.check();
}
public String caculate() {
while (isEnd(str)) {
p2 = str.indexOf(“)”);
if (p2 != -1) {
s = str.substring(0, p2);
p1 = s.lastIndexOf(“(“);
s = str.substring(p1 + 1, p2);
if (!s.equals(“”)) {
s = this.caculateNumber(s);
if (p2 == (str.length() – 1))
str = str.substring(0, p1) + s;
else
str = str.substring(0, p1) + s + str.substring(p2 + 1);
} else {
str = str.substring(0, p1) + str.substring(p2 + 1);
}
} else
str = this.caculateNumber(str);
}
return str;
}
private String caculateNumber(String ss) {
int p3 = 0, p4 = 0, p5 = 0;
char b = ‘ ‘, c = ‘ ‘;
String s1 = null, s2 = null;
double d1 = 0.0, d2 = 0.0, d3 = 0.0;
if (ss.charAt(0) == ‘+’) {
ss = ss.substring(1);
if (ss.indexOf(“+”) == -1 ss.indexOf(“-“) == -1
ss.indexOf(“*”) == -1 ss.indexOf(“/”) == -1)
return ss;
} else if (ss.charAt(0) == ‘-‘) {
if (ss.indexOf(“+”, 1) == -1 ss.indexOf(“-“, 1) == -1
ss.indexOf(“*”, 1) == -1 ss.indexOf(“/”, 1) == -1)
return ss;
}
while (isEnd2(ss)) {
p3 = 0;
p4 = 0;
p5 = 0;
if (ss.indexOf(“*”) == -1 ss.indexOf(“/”) == -1) {
for (int i = 0; i ss.length(); i++) {
b = ss.charAt(i);
if (b == ‘+’ || b == ‘-‘) {
if (p3 == 0 i != 0) {
p3 = i;
c = b;
} else if (p3 != 0 i != (p3 + 1)) {
p4 = i;
break;
}
}
}
if (p4 == 0) {
s1 = ss.substring(0, p3);
s2 = ss.substring(p3 + 1);
} else {
s1 = ss.substring(0, p3);
s2 = ss.substring(p3 + 1, p4);
}
d1 = Double.parseDouble(s1);
d2 = Double.parseDouble(s2);
if (c == ‘+’)
d3 = d1 + d2;
else if (c == ‘-‘)
d3 = d1 – d2;
if (p4 == 0)
ss = new Double(d3).toString();
else
ss = new Double(d3).toString() + ss.substring(p4);
} else {
if (ss.indexOf(“*”) == -1) {
c = ‘/’;
p4 = ss.indexOf(“/”);
} else if (ss.indexOf(“/”) == -1) {
c = ‘*’;
p4 = ss.indexOf(“*”);
} else if (ss.indexOf(“*”) ss.indexOf(“/”)) {
c = ‘/’;
p4 = ss.indexOf(“/”);
} else if (ss.indexOf(“*”) ss.indexOf(“/”)) {
c = ‘*’;
p4 = ss.indexOf(“*”);
}
for (int i = p4 – 1; i = 0; i–) {
b = ss.charAt(i);
if (b == ‘+’ || b == ‘-‘) {
if ((i – 1) != 0 ss.charAt(i – 1) != ‘+’
ss.charAt(i – 1) != ‘-‘) {
p3 = i;
break;
} else if ((i – 1) != 0
(ss.charAt(i – 1) == ‘+’ || ss.charAt(i – 1) == ‘-‘)) {
p3 = i – 1;
break;
}
}
}
for (int i = p4 + 1; i ss.length(); i++) {
b = ss.charAt(i);
if ((b == ‘+’ || b == ‘-‘ || b == ‘*’ || b == ‘/’)
(i – 1) != p4) {
p5 = i;
break;
}
}
if (p3 == 0)
s1 = ss.substring(0, p4);
else
s1 = ss.substring(p3 + 1, p4);
if (p5 == 0)
s2 = ss.substring(p4 + 1);
else
s2 = ss.substring(p4 + 1, p5);
d1 = Double.parseDouble(s1);
d2 = Double.parseDouble(s2);
if (c == ‘*’)
d3 = d1 * d2;
else if (c == ‘/’)
d3 = d1 / d2;
if (p3 == 0 p5 == 0)
ss = new Double(d3).toString();
else if (p3 == 0 p5 != 0)
ss = new Double(d3).toString() + ss.substring(p5);
else if (p3 != 0 p5 == 0)
ss = ss.substring(0, p3 + 1) + new Double(d3).toString();
else if (p3 != 0 p5 != 0)
ss = ss.substring(0, p3 + 1) + new Double(d3).toString()
+ ss.substring(p5);
}
}
return ss;
}
private boolean isEnd(String str) {
if (str.indexOf(“(“) != -1 || str.indexOf(“)”) != -1
|| str.indexOf(“+”, 1) != -1 || str.indexOf(“-“, 1) != -1
|| str.indexOf(“*”, 1) != -1 || str.indexOf(“/”, 1) != -1)
return true;
return false;
}
private boolean isEnd2(String ss) {
if (ss.indexOf(“+”, 1) != -1 || ss.indexOf(“-“, 1) != -1
|| ss.indexOf(“*”, 1) != -1 || ss.indexOf(“/”, 1) != -1)
return true;
return false;
}
private void clear() {
str = str.replaceAll(” “, “”);
}
private void check() {
int right = 0, left = 0;
for (int i = 0; i str.length(); i++) {
char a = str.charAt(i);
if (a != ‘0’ a != ‘1’ a != ‘2’ a != ‘3’ a != ‘4’
a != ‘5’ a != ‘6’ a != ‘7’ a != ‘8’ a != ‘9’
a != ‘+’ a != ‘-‘ a != ‘*’ a != ‘/’ a != ‘(‘
a != ‘)’ a != ‘.’) {
System.exit(0);
}
if (a == ‘(‘)
left++;
else if (a == ‘)’)
right++;
}
if (left != right) {
System.exit(0);
}
}
public static void main(String args[]) {
System.out.println(new CaculateString(“((1-(0/3))*7)+8”).caculate());
}
}
java算術運算測試系統怎麼保存答題記錄？
簡單的可以用文本文件（如.txt、.xml、.json保存），這些Java都有對應的包；
複雜一點的可以使用資料庫存儲。
java課程設計「小學算術運算測試程序」
花了好幾個小時,測試通過,希望樓主多給點分
import java.util.Scanner;
class Question{
private int firstParam;
private int secondParam;
private String operator;
private int answer;
private int score;
public int getFirstParam() {
return firstParam;
}
public void setFirstParam(int firstParam) {
this.firstParam = firstParam;
}
public int getSecondParam() {
return secondParam;
}
public void setSecondParam(int secondParam) {
this.secondParam = secondParam;
}
public String getOperator() {
return operator;
}
public void setOperator(String operator) {
this.operator = operator;
}
public int getAnswer() {
return answer;
}
public void setAnswer(int answer) {
this.answer = answer;
}
public int getScore() {
return score;
}
public void setScore(int score) {
this.score = score;
}
//構造
public Question(int firstParam, int secondParam) {
this.firstParam = firstParam;
this.secondParam = secondParam;
}
}
public class StudentStudy {
private int questionNumber;
private String operator;
private Question[] questions;
private int rightNumber=0;
private int wrongNumber=0;
public String getOperator() {
return operator;
}
public void setOperator(String operator) {
this.operator = operator;
}
public int getQuestionNumber() {
return questionNumber;
}
public void setQuestionNumber(int questionNumber) {
this.questionNumber = questionNumber;
}
public int getRightNumber() {
return rightNumber;
}
public void setRightNumber(int rightNumber) {
this.rightNumber = rightNumber;
}
public int getWrongNumber() {
return wrongNumber;
}
public void setWrongNumber(int wrongNumber) {
this.wrongNumber = wrongNumber;
}
public Question[] getQuestions() {
return questions;
}
public void setQuestions(Question[] questions) {
this.questions = questions;
}
public int getRandom(){
return (int)(Math.random()*10);
}
public int calculateByOperator(String operator,int first,int second){
switch(operator.charAt(0)){
case ‘+’:
return first+second;
case ‘-‘:
return first-second;
default:
return 0;
}
}
public void makeQuestion(){
mywhile:
while(questions[questionNumber-1]==null){
Question question=new Question(getRandom(),getRandom());
for(int i=0;questions[i]!=nulliquestionNumber;i++){
if((question.getFirstParam()==questions[i].getFirstParam())(question.getSecondParam()==questions[i].getSecondParam())){
continue mywhile;
}
}
for(int i=0;iquestionNumber;i++){
if(questions[i]==null){
questions[i]=question;
questions[i].setOperator(operator);
questions[i].setScore(100/questionNumber);
questions[i].setAnswer(calculateByOperator(operator,questions[i].getFirstParam(),questions[i].getSecondParam()));
break;
}
}
}
}
public StudentStudy(int questionNumber){
this.questionNumber=questionNumber;
questions=new Question[this.questionNumber];
}
public static void main(String[] args){
Scanner input=new Scanner(System.in);
System.out.println(“現在開始測試,請填寫要測試的試題數量(1-100):”);
int number=input.nextInt();
StudentStudy ss=new StudentStudy(number);
System.out.println(“請選擇要測試的試題類型:1加法2減法”);
int type=input.nextInt();
switch(type){
case 1:
ss.setOperator(“+”);
break;
case 2:
ss.setOperator(“-“);
break;
default:
System.out.println(“輸入有誤,退出系統!”);
System.exit(0);
}
ss.makeQuestion();
for(int i=0;inumber;i++){
System.out.println(“第”+(i+1)+”題:”+ss.getQuestions()[i].getFirstParam()+ss.getQuestions()[i].getOperator()+ss.getQuestions()[i].getSecondParam()+”=?”);
int answer=input.nextInt();
if(ss.getQuestions()[i].getAnswer()==answer){
ss.setRightNumber(ss.getRightNumber()+1);
System.out.println(“回答正確!”);
}
else{
ss.setWrongNumber(ss.getWrongNumber()+1);
System.out.println(“回答錯誤!”);
}
}
System.out.println(“您總共答了”+ss.getQuestionNumber()+”道題,答對”+ss.getRightNumber()+”道,答錯”+ss.getWrongNumber()+”道,最後總分為:”+ss.getRightNumber()*100/ss.getQuestionNumber()+”分”);
}
}
java做一個算術測試頁面
首先是選擇程序是做cs的還是bs的，bs比較方便，做jsp頁面，打開兩個瀏覽器，一個窗口顯示一個，一個顯示學前班模式，一個顯示小學模式
生成演算法也簡單，不管加法還是減法都生成一個2但小於上限（10或100）的數，比如98，然後生成一個比它小的數，最後一個就是它減去第二個數。如果是加法，則用第2、3個數作為提設，如果是減法，則用第1、2個數作為提設
原創文章，作者：EHSC，如若轉載，請註明出處：https://www.506064.com/zh-tw/n/145439.html
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