Python 程序：從列表中刪除重複項

編寫一個 Python 程序，從給定的列表中刪除所有重複項。Python 集合不允許重複，所以我們可以將列錶轉換為集合，然後將其轉換回列表將刪除列表重複。

# Remove Duplicates from List

dupList = [1, 2, 3, 2, 4, 8, 9, 1, 7, 6, 4, 5]
print("List Items = ", dupList)

uniqSet = set(dupList)
uniqList = list(uniqSet)

print("List Items after removing Duplicates = ", uniqList)

Python 使用設置輸出 移除列表中的重複項

List Items =  [1, 2, 3, 2, 4, 8, 9, 1, 7, 6, 4, 5]
List Items after removing Duplicates =  [1, 2, 3, 4, 5, 6, 7, 8, 9]

從列表中刪除重複項目的 Python 程序

這個 Python 程序允許輸入列表大小和項目。for 循環將迭代雙工項。帶有 not in 運算符的 if 語句檢查該值是否不在優衣庫列表中。如果為真，則將該值追加到優衣庫列表中。

# Remove Duplicates from List

dupList = []

listNumber = int(input("Enter the Total List Items = "))
for i in range(1, listNumber + 1):
    listValue = int(input("Enter the %d List Item = " %i))
    dupList.append(listValue)

print("List Items = ", dupList)

uniqList = []

for val in dupList:
    if val not in uniqList:
        uniqList.append(val)

print("List Items after removing Duplicates = ", uniqList)

在這個例子中，我們使用 Python 列表理解從列表中移除重複的項目。這段代碼與上面的例子相同，但是我們使用了列表理解的概念。

# Remove Duplicates from List

dupList = [1, 2, 5, 8, 1, 9, 11, 5, 22, 6, 2, 8, 14]

print("List Items = ", dupList)

uniqList = []
[uniqList.append(i) for i in dupList if i not in uniqList]

print("List Items after removing Duplicates = ", uniqList)

List Items =  [1, 2, 5, 8, 1, 9, 11, 5, 22, 6, 2, 8, 14]
List Items after removing Duplicates =  [1, 2, 5, 8, 9, 11, 22, 6, 14]

在本例中，我們從集合中導入了 OrderedDict，並使用 fromkeys 函數刪除重複項。別忘了把結果轉換成列表。

# Remove Duplicates from List

from collections import OrderedDict

dupList = [8, 1, 9, 2, 8, 4, 9, 11, 5, 22, 6, 4, 8]

print("List Items = ", dupList)

uniqList = OrderedDict.fromkeys(dupList)

print("List Items after removing Duplicates = ", list(uniqList))

使用排序從集合輸出中刪除列表中的重複項

List Items =  [8, 1, 9, 2, 8, 4, 9, 11, 5, 22, 6, 4, 8]
List Items after removing Duplicates =  [8, 1, 9, 2, 4, 11, 5, 22, 6]

numpy 和pands模塊都有去除重複的獨特功能，所以我們使用了相同的功能，並將結果轉換為列表。為了轉換結果，我們使用了 tolist()函數。

# Remove Duplicates from List

import numpy as np
import pandas as pd

dupList = [1, 2, 2, 4, 1, 5, 6, 8, 6, 8, 9, 7, 4]
print("List Items = ", dupList)

uniqList = np.unique(dupList).tolist()
print("List Items after removing Duplicates = ", uniqList)

uniqList2 = pd.unique(dupList).tolist()
print("List Items after removing Duplicates = ", uniqList2)

使用 numpy 唯一功能輸出 刪除列表中的重複項

List Items =  [1, 2, 2, 4, 1, 5, 6, 8, 6, 8, 9, 7, 4]
List Items after removing Duplicates =  [1, 2, 4, 5, 6, 7, 8, 9]
List Items after removing Duplicates =  [1, 2, 4, 5, 6, 8, 9, 7]

使用枚舉從列表中刪除重複項的 Python 程序。

# Remove Duplicates from List

from collections import OrderedDict

dupList = [1, 2, 3, 2, 4, 1, 5, 6, 5, 8, 7, 9, 8]

print("List Items = ", dupList)

uniqList = [val for x, val in enumerate(dupList) if val not in dupList[:x]]

print("List Items after removing Duplicates = ", uniqList)

使用枚舉輸出刪除列表中的重複項

List Items =  [1, 2, 3, 2, 4, 1, 5, 6, 5, 8, 7, 9, 8]
List Items after removing Duplicates =  [1, 2, 3, 4, 5, 6, 8, 7, 9]