編寫一個 Python 程序來檢查一個數字是不是 Pronic 數字,或者是否使用 while 循環。例如,如果一個數等於兩個連續數的乘積,則它是一個 Pronic 數,這意味着 number = n(n + 1)。
在這個 Python 程序中,I 值從零迭代到該數字的平方根,並檢查任意兩個連續數字的乘積是否等於實際數字。如果為真,標誌值變為 1,break 語句將退出循環。如果標誌等於 1,則它是一個 Pronic 數。
import math
Number = int(input("Enter the Number to Check Pronic Number = "))
i = 0
flag = 0
while i <= (int) (math.sqrt(Number)):
if Number == i * (i + 1):
flag = 1
break
i = i + 1
if flag == 1:
print("\n%d is a Pronic Number." %Number)
else:
print("%d is Not a Pronic Number." %Number)
Python 程序,使用 for 循環檢查給定的數字是否是 Pronic 數字。
Number = int(input("Enter the Number to Check Pronic Number = "))
flag = 0
for i in range(Number + 1):
if Number == i * (i + 1):
flag = 1
break
if flag == 1:
print("\n%d is a Pronic Number." %Number)
else:
print("%d is Not a Pronic Number." %Number)
Enter the Number to Check Pronic Number = 42
42 is a Pronic Number.
Enter the Number to Check Pronic Number = 55
55 is Not a Pronic Number.
Python 程序查找一個數字是不是 Pronic 數或者不使用函數。
def pronicNumber(Number):
flag = 0
for i in range(Number + 1):
if Number == i * (i + 1):
flag = 1
break
return flag
Number = int(input("Enter the Number to Check Pronic Number = "))
if pronicNumber(Number) == 1:
print("\n%d is a Pronic Number." %Number)
else:
print("%d is Not a Pronic Number." %Number)
Enter the Number to Check Pronic Number = 52
52 is Not a Pronic Number.
Enter the Number to Check Pronic Number = 72
72 is a Pronic Number.
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