js解密的代碼（js解密什麼意思）

本文目錄一覽：

• 1、js代碼解密
• 2、計算機代碼Js解密
• 3、JS代碼解密
• 4、JS代碼解密？

js代碼解密

像這樣的混淆代碼, 最終都會調用eval來運行加密的代碼

觀察你給的這一段, 發現\u0065\u0076\u0061\u006c, 剛好就代表了eval函數

把它刪去再運行這一段得到

var _token = “jmm8qvq”;

後面還有一段很長的, 同理刪去eval函數就能得到原始代碼

計算機代碼Js解密

window[“\x65\x76\x61\x6c”]( …. )

// 即window[‘eval’], 把括號里的文字作為代碼執行

(function(EhFnhw1,tovOUpsAX2,MsHiKK3,RtpVa4,UT5,YbVn6){UT5=function(MsHiKK3){return(MsHiKK3tovOUpsAX2?””:UT5(window[“\x70\x61\x72\x73\x65\x49\x6e\x74”](MsHiKK3/tovOUpsAX2)))+((MsHiKK3=MsHiKK3%tovOUpsAX2)35?window[“\x53\x74\x72\x69\x6e\x67”][“\x66\x72\x6f\x6d\x43\x68\x61\x72\x43\x6f\x64\x65”](MsHiKK3+29):MsHiKK3[“\x74\x6f\x53\x74\x72\x69\x6e\x67″](36))};if(!”[“\x72\x65\x70\x6c\x61\x63\x65”](/^/,window[“\x53\x74\x72\x69\x6e\x67”])){while(MsHiKK3–)YbVn6[UT5(MsHiKK3)]=RtpVa4[MsHiKK3]||UT5(MsHiKK3);RtpVa4=[function(UT5){return YbVn6[UT5]}];UT5=function(){return’\\\x77\x2b’};MsHiKK3=1;};while(MsHiKK3–)if(RtpVa4[MsHiKK3])EhFnhw1=EhFnhw1[“\x72\x65\x70\x6c\x61\x63\x65”](new window[“\x52\x65\x67\x45\x78\x70”](‘\\\x62’+UT5(MsHiKK3)+’\\\x62′,’\x67’),RtpVa4[MsHiKK3]);return EhFnhw1;}(‘\x32\x28\x31\x28\x29\x7b\x30\x2e\x33\x3d\x22\x36\x3a\x35\x22\x7d\x2c\x34\x29\x3b’,7,7,’\x64\x6f\x63\x75\x6d\x65\x6e\x74\x7c\x66\x75\x6e\x63\x74\x69\x6f\x6e\x7c\x73\x65\x74\x49\x6e\x74\x65\x72\x76\x61\x6c\x7c\x74\x69\x74\x6c\x65\x7c\x32\x30\x30\x30\x7c\x61\x77\x65\x73\x6f\x6d\x65\x7c\x61\x6e\x73\x77\x65\x72′[“\x73\x70\x6c\x69\x74”](‘\x7c’),0,{}))

// 這一大串的結果是

“setInterval(function(){document.title=”answer:awesome”},2000);”

// 即設置一個時鐘, 每2秒把標題修改為answer:awesome

JS代碼解密

(function(E, B) {

function ka(a, b, d) {

if (d === B a.nodeType === 1) {

d = a.getAttribute(“data-” + b);

if (typeof d === “string”) {

try {

d = d === “true” ? true: d === “false” ? false: d === “null” ? null: !c.isNaN(d) ? parseFloat(d) : Ja.test(d) ? c.parseJSON(d) : d

} catch(e) {}

c.data(a, b, d)

} else d = B

}

return d

}

function U() {

return false

}

function ca() {

return true

}

function la(a, b, d) {

d[0].type = a;

return c.event.handle.apply(b, d)

}

function Ka(a) {

var b, d, e, f, h, l, k, o, x, r, A, C = [];

f = [];

h = c.data(this, this.nodeType ? “events”: “__events__”);

if (typeof h === “function”) h = h.events;

if (! (a.liveFired === this || !h || !h.live || a.button a.type === “click”)) {

if (a.namespace) A = RegExp(“(^|\\.)” + a.namespace.split(“.”).join(“\\.(?:.*\\.)?”) + “(\\.|$)”);

a.liveFired = this;

var J = h.live.slice(0);

for (k = 0; k J.length; k++) {

h = J[k];

h.origType.replace(X, “”) === a.type ? f.push(h.selector) : J.splice(k–, 1)

}

f = c(a.target).closest(f, a.currentTarget);

o = 0;

for (x = f.length; o x; o++) {

r = f[o];

for (k = 0; k J.length; k++) {

h = J[k];

if (r.selector === h.selector (!A || A.test(h.namespace))) {

l = r.elem;

e = null;

if (h.preType === “mouseenter” || h.preType === “mouseleave”) {

a.type = h.preType;

e = c(a.relatedTarget).closest(h.selector)[0]

}

if (!e || e !== l) C.push({

elem: l,

handleObj: h,

level: r.level

})

}

}

}

o = 0;

for (x = C.length; o x; o++) {

f = C[o];

if (d f.level d)

JS代碼解密？

沒法解密 一個是這種根本沒法逆向，（如果是開發者的話，如果是打包的js文件，會有個map，可以還原回去，但是這種