Python 程序：檢查元組中存在的項目

編寫一個 Python 程序來檢查給定的項是否存在於元組中。我們使用 in 運算符來查找元組中存在的項。

# Check Element Presnet in Tuple

numTuple = (4, 6, 8, 11, 22, 43, 58, 99, 16)
print("Tuple Items = ", numTuple)

number = int(input("Enter Tuple Item to Find = "))

result = number in numTuple

print("Does our numTuple Contains the ", number, "? ", result)

雖然上面的例子返回真或假，我們需要一個有意義的消息。因此，如果元組中存在條目，我們使用 if 語句和 in 運算符(numTuple 中的 If 數字)來打印不同的消息。

# Check Element Presnet in Tuple

numTuple = (4, 6, 8, 11, 22, 43, 58, 99, 16)
print("Tuple Items = ", numTuple)

number = int(input("Enter Tuple Item to Find = "))

if number in numTuple:
    print(number, " is in the numTuple")
else:
    print("Sorry! We haven't found ", number, " in numTuple")

Tuple Items =  (4, 6, 8, 11, 22, 43, 58, 99, 16)
Enter Tuple Item to Find = 22
22  is in the numTuple
>>> 
Tuple Items =  (4, 6, 8, 11, 22, 43, 58, 99, 16)
Enter Tuple Item to Find = 124
Sorry! We haven't found  124  in numTuple
>>> 

使用 For 循環檢查元組中是否存在項目的 Python 程序

在這個 Python 示例中，我們使用 if 語句(if val == number)對照給定的數字檢查每個元組項。如果為真，則結果為真，編譯器將從 for 循環中斷開。

# Check Element Presnet in Tuple

numTuple = (4, 6, 8, 11, 22, 43, 58, 99, 16)
print("Tuple Items = ", numTuple)

number = int(input("Enter Tuple Item to Find = "))

result = False

for val in numTuple:
    if val == number:
        result = True
        break

print("Does our numTuple Contains the ", number, "? ", result)

Tuple Items =  (4, 6, 8, 11, 22, 43, 58, 99, 16)
Enter Tuple Item to Find = 16
Does our numTuple Contains the  16 ?  True