编写一个 Python 程序，从给定的列表中删除所有重复项。Python 集合不允许重复，所以我们可以将列表转换为集合，然后将其转换回列表将删除列表重复。
# Remove Duplicates from List
dupList = [1, 2, 3, 2, 4, 8, 9, 1, 7, 6, 4, 5]
print("List Items = ", dupList)
uniqSet = set(dupList)
uniqList = list(uniqSet)
print("List Items after removing Duplicates = ", uniqList)Python 使用设置输出 移除列表中的重复项
List Items = [1, 2, 3, 2, 4, 8, 9, 1, 7, 6, 4, 5]
List Items after removing Duplicates = [1, 2, 3, 4, 5, 6, 7, 8, 9]从列表中删除重复项目的 Python 程序
这个 Python 程序允许输入列表大小和项目。for 循环将迭代双工项。带有 not in 运算符的 if 语句检查该值是否不在优衣库列表中。如果为真，则将该值追加到优衣库列表中。
# Remove Duplicates from List
dupList = []
listNumber = int(input("Enter the Total List Items = "))
for i in range(1, listNumber + 1):
listValue = int(input("Enter the %d List Item = " %i))
dupList.append(listValue)
print("List Items = ", dupList)
uniqList = []
for val in dupList:
if val not in uniqList:
uniqList.append(val)
print("List Items after removing Duplicates = ", uniqList)在这个例子中，我们使用 Python 列表理解从列表中移除重复的项目。这段代码与上面的例子相同，但是我们使用了列表理解的概念。
# Remove Duplicates from List
dupList = [1, 2, 5, 8, 1, 9, 11, 5, 22, 6, 2, 8, 14]
print("List Items = ", dupList)
uniqList = []
[uniqList.append(i) for i in dupList if i not in uniqList]
print("List Items after removing Duplicates = ", uniqList)List Items = [1, 2, 5, 8, 1, 9, 11, 5, 22, 6, 2, 8, 14]
List Items after removing Duplicates = [1, 2, 5, 8, 9, 11, 22, 6, 14]在本例中，我们从集合中导入了 OrderedDict，并使用 fromkeys 函数删除重复项。别忘了把结果转换成列表。
# Remove Duplicates from List
from collections import OrderedDict
dupList = [8, 1, 9, 2, 8, 4, 9, 11, 5, 22, 6, 4, 8]
print("List Items = ", dupList)
uniqList = OrderedDict.fromkeys(dupList)
print("List Items after removing Duplicates = ", list(uniqList))使用排序从集合输出中删除列表中的重复项
List Items = [8, 1, 9, 2, 8, 4, 9, 11, 5, 22, 6, 4, 8]
List Items after removing Duplicates = [8, 1, 9, 2, 4, 11, 5, 22, 6]numpy 和pands模块都有去除重复的独特功能，所以我们使用了相同的功能，并将结果转换为列表。为了转换结果，我们使用了 tolist()函数。
# Remove Duplicates from List
import numpy as np
import pandas as pd
dupList = [1, 2, 2, 4, 1, 5, 6, 8, 6, 8, 9, 7, 4]
print("List Items = ", dupList)
uniqList = np.unique(dupList).tolist()
print("List Items after removing Duplicates = ", uniqList)
uniqList2 = pd.unique(dupList).tolist()
print("List Items after removing Duplicates = ", uniqList2)使用 numpy 唯一功能输出 删除列表中的重复项
List Items = [1, 2, 2, 4, 1, 5, 6, 8, 6, 8, 9, 7, 4]
List Items after removing Duplicates = [1, 2, 4, 5, 6, 7, 8, 9]
List Items after removing Duplicates = [1, 2, 4, 5, 6, 8, 9, 7]使用枚举从列表中删除重复项的 Python 程序。
# Remove Duplicates from List
from collections import OrderedDict
dupList = [1, 2, 3, 2, 4, 1, 5, 6, 5, 8, 7, 9, 8]
print("List Items = ", dupList)
uniqList = [val for x, val in enumerate(dupList) if val not in dupList[:x]]
print("List Items after removing Duplicates = ", uniqList)使用枚举输出删除列表中的重复项
List Items = [1, 2, 3, 2, 4, 1, 5, 6, 5, 8, 7, 9, 8]
List Items after removing Duplicates = [1, 2, 3, 4, 5, 6, 8, 7, 9]原创文章，作者：小蓝，如若转载，请注明出处：https://www.506064.com/n/254192.html
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