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C语言中如何实现多组数据输入输出？
您好：#include iostream
#include stdlib.h
using namespace std;
int main()
{
int n;
int a[50000];
while (cinn) //当没有n输入的时候结束循环，可以按 ctrl+z 来输入结束符EOF
{
for (int i=0;i50000;i++)
a[i]=0;
for (int i=0;in;i++)
{
int temp;
cintemp;
a[temp]=temp;
}
for (int i=0;i50000;i++)
{
if (a[i] != 0)
couta[i]” “;
}
}
system(“pause”);
return 0;
}
追问
先谢谢你。但是这段代码不是我想要的，我也写过。
当输完第一组：
5
1 2 5 4 5
回车之后，马上输出第一组的结果：
1 2 4 5
我想线不输出第一组的结果，等我把第二个case输进去之后，按ctrl + Z 后再输出两个case的结果。
C语言如何多组数据输入输出
#includeintpow(inta,intn)//计算a的n次方{if(n==1)returna;returna*pow(a,n-1);}intmain(){intT;intn,k,sum,i;scanf(“%d”,T);while(T–){sum=0;scanf(“%d%d”,n,k);for(i=1;i
C语言中如何实现多组数据输入输出
仔细认真看看下面的会对你有帮助的，嘿嘿
输入格式：有多个case输入，直到文件结束
输出格式：一行一个结果
Problem Description
Your task is to Calculate a + b.
Too easy?! Of course! I specially designed the problem for acm beginners.
You must have found that some problems have the same titles with this one, yes, all these problems were designed for the same aim.
Input
The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.
Output
For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.
Sample Input
1 5
10 20
Sample Output
6
30
Author
lcy
Recommend
JGShining
#include stdio.h
int main()
{
int a,b;
while( scanf( “%d%d” , a , b ) != EOF ) //输入直到文件结尾
{
printf( “%d\n” , a+b ); //一行一个结果
}
return 0;
}
HDOJ1090
输入格式：先输入有case数，再依次输入每个case
输出格式：一行一个结果
#include stdio.h
Problem Description
Your task is to Calculate a + b.
Input
Input contains an integer N in the first line, and then N lines follow. Each line consists of a pair of integers a and b, separated by a space, one pair of integers per line.
Output
For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.
Sample Input
2
1 5
10 20
Sample Output
6
30
Author
lcy
Recommend
JGShining
int main()
{ int n,a,b;
scanf( “%d” , n ); //输入的case数
while( n– ) //控制输入
{ scanf( “%d%d” , a , b );
printf( “%d\n” , a+b ); //一行一个结果
}
return 0;
}
HDOJ1091
输入格式：每行输入一组case，当case中的数据满足某种情况时退出
输出格式：一行一个结果
Problem Description
Your task is to Calculate a + b.
Input
Input contains multiple test cases. Each test case contains a pair of integers a and b, one pair of integers per line. A test case containing 0 0 terminates the input and this test case is not to be processed.
Output
For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input.
Sample Input
1 5
10 20
0 0
Sample Output
6
30
Author
lcy
Recommend
JGShining
#include stdio.h
int main()
{
int a,b;
while( scanf( “%d%d” , a , b ) (a||b) ) //输入直到满足a和b均为0结束
{
printf( “%d\n” , a+b ); //一行一个结果
}
return 0;
}
HDOJ1092
输入格式：每组case前有一个控制输入个数的数，当这个数为0结束
输出格式：一行一个结果
#include stdio.h
Problem Description
Your task is to Calculate the sum of some integers.
Input
Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.
Output
For each group of input integers you should output their sum in one line, and with one line of output for each line in input.
Sample Input
4 1 2 3 4
5 1 2 3 4 5
Sample Output
10
15
Author
lcy
Recommend
JGShining
int main()
{
int n,sum;
while( scanf( “%d” , n ) n ) //每组case前有一个控制该组输入数据的数，为0结束
{
int x;
sum = 0;
while( n– ) //控制该组输入个数
{
scanf( “%d” , x );
sum += x;
}
printf( “%d\n” , sum ); //一行一个结果
}
return 0;
}
HDOJ1093
输入格式：一开始有一个控制总的输入case的数，而每个case中又有一个控制该组输入数据的数
输出格式：一行一个结果
Problem Description
Your task is to calculate the sum of some integers.
Input
Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.
Output
For each group of input integers you should output their sum in one line, and with one line of output for each line in input.
Sample Input
2
4 1 2 3 4
5 1 2 3 4 5
Sample Output
10
15
Author
lcy
5
#include stdio.h
int main()
{
int casnum,n,sum;
scanf( “%d” , casnum ); //控制总的输入case的数
while( casnum– ) //控制总的输入个数
{
int x;
sum = 0;
scanf( “%d” , n ); //每个case中控制该组输入个数
while( n– )
{
scanf( “%d” , x );
sum += x;
}
printf( “%d\n” , sum ); //一行一个结果
}
return 0;
}
HDOJ1094
输入格式：总的case是输到文件结尾，每个case中的一开始要输入一个控制该组个数的数
输出格式：一行一个结果
Problem Description
Your task is to calculate the sum of some integers.
Input
Input contains multiple test cases, and one case one line. Each case starts with an integer N, and then N integers follow in the same line.
Output
For each test case you should output the sum of N integers in one line, and with one line of output for each line in input.
Sample Input
4 1 2 3 4
5 1 2 3 4 5
Sample Output
10
15
6
#include stdio.h
int main()
{
int n,sum;
while( scanf( “%d” , n ) != EOF ) //输出到文件结尾
{
int x;
sum = 0;
while( n– ) //控制该组输入个数
{
scanf( “%d” , x );
sum += x;
}
printf( “%d\n” , sum ); //一行一个结果
}
return 0;
}
HDOJ1095
输入格式：输入直到文件结束
输出格式：一行一个结果，结果输完后还有一个blank line
Problem Description
Your task is to Calculate a + b.
Input
The input will consist of a series of pairs of integers a and b, separated by a space, one pair of integers per line.
Output
For each pair of input integers a and b you should output the sum of a and b, and followed by a blank line.
Sample Input
1 5
10 20
Sample Output
6
30
7
#include stdio.h
int main()
{
int a,b;
while( scanf( “%d%d” , a , b ) != EOF ) //输入直到文件结束
{
printf( “%d\n\n” , a+b ); //一行一个结果，结果输完后还有一个回车
}
return 0;
}
HDOJ1096
输入格式：一开始输入总的case数，每组case一开始有控制该组输入个数的数
输出格式：一行一个结果，两个结果之间有一个回车，注意最后一个case的处理。
Problem Description
Your task is to calculate the sum of some integers.
Input
Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.
Output
For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.
Sample Input
3
4 1 2 3 4
5 1 2 3 4 5
3 1 2 3
Sample Output
10
15
6
#include stdio.h
int main()
{
int casnum,n,sum;
scanf( “%d” , casnum ); //总的输入case数
while( casnum– ) //控制输入组数
{
int x;
sum = 0;
scanf( “%d” , n ); //控制每组的输入个数
while( n– )
{
scanf( “%d” , x );
sum += x;
}
printf( “%d\n” , sum ); //一行一个结果
if( casnum ) printf( “\n” ); //两两结果之间有一个回车，最后一个结果后面没有
}
return 0;
}
c语言中，一次连续输入多组数据，并且最后连续输出多组结果，应该用哪种方法
用二维数组就可以实现一次连续输入多组数据。思路是嵌套循环，外层循环控制二维数组的行数（也就是第几组数据），内层循环控制这组数据中数据个数。
采用二维数组方法的有点在于，这种随机存取的数据结构方便查找和检索，但一定要注意这种方法不便于向已有数据中插入和删除数据。
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