c语言个税计算,c语言个税计算程序

本文目录一览：

• 1、C语言个人所得税计算系统
• 2、C语言计算个人所得税 编程
• 3、C语言，个人所得税计算，求大神回答- -悬赏有点少

C语言个人所得税计算系统

这样看能不能符合你的要求，说实话，分好少！不行的话可以追问

includestdio.h

void main()

{

double insure1=0.18; //个人承担保险金

double insure2=0.29; //他人承担保险金

int charge=3500; //费用扣除额

int pay=0； //基本工资

int fast=0; //速算金额

double cass=0.0; //税率

double ratepaying=0.0; //应纳税所得额

int type; //是又个人承担的，还是他人代付

double sum=0.0;

printf(“请输入你当月取得的工资收入:%d”,pay);

scanf(“%d”,pay);

printf(“个人所得税是由谁承担？(0:自己，1:他人代付)：% d”,type)

scanf(“%d”,type);

if(type==0)

{

ratepaying=pay-pay*insure-charge;

if(ratepaying=1500)

{

cass=0.03;

fast=0;

}

else if(ratepaying1500 ratepaying=4500)

{

cass=0.1;

fast=105;

}

else if(ratepaying4500 ratepaying=9000)

{

cass=0.2;

fast=555;

}

else if(ratepaying9000 ratepaying=35000)

{

cass=0.25;

fast=1005;

}

else if(ratepaying35000 ratepaying=55000)

{

cass=0.3;

fast=2755;

}

else if(ratepaying55000 ratepaying=80000)

{

cass=0.35;

fast=5505;

}

else

{

cass=0.45;

fast=13505;

}

sum=ratepaying*cass-fast;

printf(“应纳个人所得税税额为:%.2lf”,sum)

}

else

{

ratepaying=pay-pay*insure-charge;

if(ratepaying=1455)

{

cass=0.03;

fast=0;

}

else if(ratepaying1455 ratepaying=4155)

{

cass=0.1;

fast=105;

}

else if(ratepaying4155 ratepaying=7755)

{

cass=0.2;

fast=555;

}

else if(ratepaying7755 ratepaying=27255)

{

cass=0.25;

fast=1005;

}

else if(ratepaying27255 ratepaying=41255)

{

cass=0.3;

fast=2755;

}

else if(ratepaying41255 ratepaying=57505)

{

cass=0.35;

fast=5505;

}

else

{

cass=0.45;

fast=13505;

}

sum=ratepaying*cass-fast;

printf(“应纳个人所得税税额为:%.2lf”,sum)

}

}

C语言计算个人所得税 编程

#include stdio.h

#include stdlib.h

int jishu(double x)

{

 if(0xx=500)

  return 1;

 else if(500xx=2000)

  return 2;

 else if(2000xx=5000)

  return 3;

 else if(5000xx=20000)

  return 4;

 else if(20000xx=40000)

  return 5;

 else if(40000xx=60000)

  return 6;

 else if(60000xx=80000)

  return 7;

 else if(80000xx=100000)

  return 8;

 else

  return 9;

}

main()

{

 double rate[10]={0.0,0.05,0.1,0.15,0.2,0.25,0.3,0.35,0.4,0.45};

 int a[10]={0,0,25,125,375,1375,3375,6375,10375,15375};

 double n,m,l;

 int i;

 printf(“请输入工资：”);

 scanf(“%lf”,l);

 if(l=3500)

  printf(“您不用交税\n”);

 else

 {

  n=l-3500.0;

  i=jishu(n);

  m=n*rate[i]-a[i];

  printf(“应缴个人所得税：%.2lf\n实发工资额：%.2lf\n”,m,l-m);

 }

}

这是按你说的计算方法

C语言，个人所得税计算，求大神回答- -悬赏有点少

#includestdio.h

double IIT(int money,int nation)

{

double iit = money;

switch(nation)

{

case 1 : iit = money – 1000 – 3500 ;break;

case 0 : iit = money – 1000 – 4800 ;break;

default: printf(“输入有误！\n”);

}

if(iit =1500) iit = iit*0.03;

else if(iit1500iit=4500) iit = (iit*0.1 – 105);

else if(iit4500iit=9000) iit = (iit*0.2 – 555);

else if(iit9000iit=35000) iit = (iit*0.25 -1005);

else if(iit35000iit=55000) iit= (iit*0.3 -2755);

else if(iit55000iit=80000) iit= (iit*0.35 -5505);

else iit = (iit*0.45 – 13505);

return iit;

}

int main()

{

int money,nation;

printf(“请确定你的国籍： 1.中国 0.外籍\n”);

scanf(“%d”,nation);

printf(“请输入您的工资： “);

scanf(“%d”,money);

if(nation == 1){

if(money = 4500)

printf(“您不需要缴纳个人所得税。\n”);

else

printf(“您要缴纳的个人所得税为： %.0f”,IIT(money,nation));

}

if(nation == 0)

{

if(money = 5800)

printf(“您不需要缴纳个人所得税。\n”);

else

printf(“您要缴纳的个人所得税为： %.0f”,IIT(money,nation));

}

return 0;

}