编写一个 Python 程序来查找元组中所有项目的总和。这里，我们使用 Tuple sum 函数返回所有 Tuple 项的总和。
# Tuple Sum of All Items
numTuple = (20, 40, 65, 75, 80, 220)
print("Tuple Items = ", numTuple)
tupleSum = sum(numTuple)
print("\nThe Sum of numTuple Tuple Items = ", tupleSum)Tuple Items = (20, 40, 65, 75, 80, 220)
The Sum of numTuple Tuple Items = 500寻找元组项之和的 Python 程序
在这个 Python 示例中，for 循环(用于 numTuple 中的 tup)迭代所有元组项。在循环(tupleSum = tupleSum + tup)中，我们将每个元组项添加到 tupleSum 中，并打印相同的内容。
# Tuple Sum of All Items
numTuple = (11, 22, 33, 44, 55, 66, 77, 88, 99)
print("Odd Tuple Items = ", numTuple)
tupleSum = 0
for tup in numTuple:
tupleSum = tupleSum + tup
print("\nThe Sum of numTuple Tuple Items = ", tupleSum)Odd Tuple Items = (11, 22, 33, 44, 55, 66, 77, 88, 99)
The Sum of numTuple Tuple Items = 495Python 程序使用 While 循环计算所有元组项的总和。
# Tuple Sum of All Items
numTuple = (25, 45, 65, 75, 95, 125, 256, 725)
print("Odd Tuple Items = ", numTuple)
tupleSum = 0
i = 0
while (i < len(numTuple)):
tupleSum = tupleSum + numTuple[i]
i = i + 1
print("\nThe Sum of numTuple Tuple Items = ", tupleSum)Odd Tuple Items = (25, 45, 65, 75, 95, 125, 256, 725)
The Sum of numTuple Tuple Items = 1411在这个 Python Tuple 示例中，我们创建了一个 sumOfTupleItems(numTuple)函数，该函数将计算并返回所有 tuple 项的总和。
# Tuple Sum
def sumOfTupleItems(numTuple):
tupleSum = 0
for tup in numTuple:
tupleSum = tupleSum + tup
return tupleSum
numTuple = (16, 31, 24, 98, 123, 78, 56, 67, 22)
print("Tuple Items = ", numTuple)
tSum = sumOfTupleItems(numTuple)
print("\nThe Sum of numTuple Tuple Items = ", tSum)原创文章，作者：ZU4PA，如若转载，请注明出处：https://www.506064.com/n/127739.html
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