编写一个 Python 程序来检查一个数字是不是 Pronic 数字，或者是否使用 while 循环。例如，如果一个数等于两个连续数的乘积，则它是一个 Pronic 数，这意味着 number = n(n + 1)。
在这个 Python 程序中，I 值从零迭代到该数字的平方根，并检查任意两个连续数字的乘积是否等于实际数字。如果为真，标志值变为 1，break 语句将退出循环。如果标志等于 1，则它是一个 Pronic 数。
import math
Number = int(input("Enter the Number to Check Pronic Number = "))
i = 0
flag = 0
while i <= (int) (math.sqrt(Number)):
if Number == i * (i + 1):
flag = 1
break
i = i + 1
if flag == 1:
print("\n%d is a Pronic Number." %Number)
else:
print("%d is Not a Pronic Number." %Number)Python 程序，使用 for 循环检查给定的数字是否是 Pronic 数字。
Number = int(input("Enter the Number to Check Pronic Number = "))
flag = 0
for i in range(Number + 1):
if Number == i * (i + 1):
flag = 1
break
if flag == 1:
print("\n%d is a Pronic Number." %Number)
else:
print("%d is Not a Pronic Number." %Number)Enter the Number to Check Pronic Number = 42
42 is a Pronic Number.
Enter the Number to Check Pronic Number = 55
55 is Not a Pronic Number.Python 程序查找一个数字是不是 Pronic 数或者不使用函数。
def pronicNumber(Number):
flag = 0
for i in range(Number + 1):
if Number == i * (i + 1):
flag = 1
break
return flag
Number = int(input("Enter the Number to Check Pronic Number = "))
if pronicNumber(Number) == 1:
print("\n%d is a Pronic Number." %Number)
else:
print("%d is Not a Pronic Number." %Number)
Enter the Number to Check Pronic Number = 52
52 is Not a Pronic Number.
Enter the Number to Check Pronic Number = 72
72 is a Pronic Number.原创文章，作者：简单一点，如若转载，请注明出处：https://www.506064.com/n/126945.html
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